V. In a parallelogram ABCD, ∠A = ( 6 X – 17 )° and ∠C = ( X + 63 )°, then ∠B = ……..
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Answered by
0
Answer:
We have,
In parallelogram ABCD
∠A=(6x−17)
o
and∠C=(x+63)
o
Find the value of ∠A
Then, We know that
∠A=∠C ∴It is aparallelogram
6x−17=x+63
6x−x=63+17
5x=80
x=16
o
Then,
∠A=6x−17
∠A=6×16−17
∠A=96−17
∠A=79
o
Hence, this is the answer.
Answered by
1
Answer:
in parallelogram opposite angle are equal
angle A= angle C
6x-17=x+63
5x=80
x=16
angle A=96-17
= 79
angle A and angle B are on the same side of parallel
angleA+angle B=180
angle B=180-79
=101
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