V Is 80 Cm Cube.Increse Gas By 20 Precent Andt Is 25 Celusi Constant P
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Answer:
V1 = 80 mL
V2 = 80 + 20/100 = 80+0.2 = 80.2 mL
T1 = 25 Celsius = 298K
T2 = ?
We have,
T2 = T1 * V2 / V1
T2 = 298*80.2 / 80
Hence, T2 = 298.75 K.
Hope it helps!!!
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