V is three years older then D six years ago.V's age was four times D age .find age of D and V
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let D's age is x
V's age = x+3
6years ago. V's age was 4 times D's age
(x+3) - 6 = 4(x-6)
⇒ x-3 = 4x - 24
⇒ x - 4x = -24 + 3
⇒ -3x = -21
⇒ x = -21/-3 = 7
D's age = 7 years
V's age = 7+3 = 10 years
V's age = x+3
6years ago. V's age was 4 times D's age
(x+3) - 6 = 4(x-6)
⇒ x-3 = 4x - 24
⇒ x - 4x = -24 + 3
⇒ -3x = -21
⇒ x = -21/-3 = 7
D's age = 7 years
V's age = 7+3 = 10 years
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