Question

V=ka^2ut is dimensionally correct or not

Answer 1

Answer:

As LHS is not equal to RHS

so it is not correct dimensionally

Explanation:

Dimensions of V= LT^-1

Dimensions of Ka2ut = [(Lt^-2)^2*Lt^-1*T)

so on solving :- L^2T^-4 *L^1t^-1*T^1

L^3T^-4

answer  :- As LHS is not equal to RHS

so it is not correct dimensionally