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Let the period of revolution of a planet at a distance 2R from a star be T. Prove that ll ll was
at a distance of SR from the star, its period of revolution will be 81.
Determine the force of gravitation letween the earth and a 60 kg boy who is standing on the
surface of earth. (R = 6400 km, M = 6 x 1024 kg, G = 6.67 x 10 Nm /kg)
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Answer:
Explanation:
According to Kepler's law ,
T² is directly propotional to a³
Here T denotes the time period and a denotes the radius of revolution
Here when the radius of revolution is R then time period is T means
T² = kR³ [ here k is proportionality constant ]----(1)
Again,
Let the time period is T' when the radius of revolution is 2R
T'² = k(2R)³ = k.8R³ -----(2)
Dividing equation (1) by (2)
T²/T'² = kR³/k8R³ = 1/8
T'² = 8T²square root both sides, we get
T' = √8 T
Hence, proved.
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