Question

(v) p(x) = x2 + 2-3x - 6
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Answer 1

Answer:

P(x)=x

2

−3x+2

Put p(x)=0, For finding zeroes of the given polynomial

⟹x

2

−3x+2=0

⟹x

2

−x−2x+2=0

⟹x(x−1)−2(x−1)=0

⟹(x−2),(x−1)=0

⟹x−2=0 , x−1=0

⟹x=2 , x=1

⟹2,1 are zeroes of the equation p(x)=x

2

−3x+2.