Math, asked by preeti122333, 6 months ago

(v) P(x) = x2 + 2V3x - 6​

Answers

Answered by kpranavachanta
1

Answer:

if they ask to find roots

x^2+2√3 x-6=0                                                      

x=\frac{-b+-\sqrt{b^2-4ac} }{2a}

x=\frac{-2\sqrt{3}+-\sqrt{(2\sqrt{3)^2}-4.1.-6 }  }{2}

x=\frac{-2\sqrt{3} +-\sqrt{12+24} }{2}

x=\frac{-2\sqrt{3} +-\sqrt{36} }{2}

x=\frac{-2\sqrt{3}+-6 }{2}

x=√3+-(6)

x=√3+6 .                               x=√3-6

Step-by-step explanation:

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