Question

(v) root2x+root3 y=0
root3x- root8 y = 0​

Answer 1

Answer:

The value of x and y is zero.                

Step-by-step explanation:

Given : Equations \sqrt{2}x+\sqrt{3}y=02x+3y=0 and \sqrt{3}x-\sqrt{8}y=03x−8y=0

To find : Solve the equations?

Solution :

\sqrt{2}x+\sqrt{3}y=02x+3y=0 ......(1)

\sqrt{3}x-\sqrt{8}y=03x−8y=0 ........(2)

Multiply equation (1) by \sqrt{3}3 and equation (2) by \sqrt{2}2

\sqrt{6}x+\sqrt{9}y=06x+9y=0 ......(3)

\sqrt{6}x-\sqrt{16}y=06x−16y=0 ........(4)

Subtract equation (3) and (4),

\sqrt{6}x+\sqrt{9}y-\sqrt{6}x+\sqrt{16}y=06x+9y−6x+16y=0

3y+4y=03y+4y=0

7y=07y=0

y=0y=0

Substitute in equation (1),

\sqrt{2}x+\sqrt{3}(0)=02x+3(0)=0

\sqrt{2}x=02x=0

x=0x=0

Therefore, The value of x and y is zero