Math, asked by AksaraRaj, 5 months ago

(v) (sin B cos C + cos B sin C)
(vi) (sec^2 C - tan^2 C)​

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Answered by narendrakillari18120
1

sinB cosC +cosBsinC

Step-by-step explanation:

AC^2+AB^2=BC^2

15^2+AC^2=17^2

AC^2=289-225

AC^2=64

AC=√64

AC=8

=(8/17).(8/17)+(15/17).(15/17)

=(64/289)+(225/289)

=(289/289)

=1

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