Math, asked by ramapanthibb, 5 months ago

(v) sin30° + cos60° + tan0°
(vi) (sin30° + cos60°) (tan60° – sec30°)​

Answers

Answered by Shalineeabhiarya
0

Step-by-step explanation:

(v) sin30° + cos60° + tan0°

= 1/2+1/2+0

= 1

(vi) (sin30° + cos60°) (tan60° – sec30°)

= (1/2+1/2)(√3-2/√3)

=1(1/√3)

= 1/√3

Answered by Plantimon
1

Answer:

Step-by-step explanation:

(v)  sin30 + cos60 + tan0

     1/2 + 1/2 + 0

     = 1

(vi)  (sin30 +cos60) (tan60 - sec30)

     (1/2 +1/2) ( 1 - 2/root 3 )

     ( 1 ) {( root 3 - 2)/ root 3 }

    ( root 3 - 2) / root 3

    rationalising the equation,

    (root 3 - 2) / root 3 mutiply root 3 / root 3

     =  (3 - 2root 3 ) / 3

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