Question

v square+4√3v-15 find zeroes

Answer 1

Hope u like my process
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$= > \: {v}^{2} + 4 \sqrt{3} v - 15 = 0 \\ \\ or. \: \: {v}^{2} + 5 \sqrt{3} v - \sqrt{3} v - 15 = 0 \\ \\ or. \: \: v(v + 5 \sqrt{3} ) - \sqrt{3} (v + 5 \sqrt{3} ) = 0 \\ \\ or. \: \: (v + 5 \sqrt{3} )(v - \sqrt{3} ) = 0 \\ \\ so \: \: \: .. \: \\ either \\ ........... \\ = > v + 5 \sqrt{3} = 0 \\ \\ or. \: \: v = - 5 \sqrt{3} \\ \\ else \\ ........ \\ = > \: v - \sqrt{3} = 0 \\ \\ or. \: \: v = \sqrt{3}$
So the required zeroes are..
$v = - 5 \sqrt{3} ....or... \sqrt{3}$
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Hope this is ur required answer

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