Physics, asked by Blacksmith1111, 7 months ago

V= t^2 m/s, the average velocity from 2 s to 4 s is:

Answers

Answered by pulakmath007
22

Answer:

Initial velocity at 2sec = 2^2 m/s = 4 m/s

Final velocity at 4 sec = 4^2 m/s = 16 m/s

So Average Velocity

= ( Initial velocity + Final velocity) /2

= ( 4 + 16 ) /2 m/s

= 20/2 m/s

= 10 m/s

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Answered by ravanji786
0

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The average speed of the particle is solved using speed_av = v_initial + v_final / 2. At t = 0 its instantaneous speed is -2 m/s and at t = 4 seconds it is 2 m/s. Solving for its average speed;

speed_av = v_initial + v_final / 2

speed_av = (-2m/s + 2 m/s) / 2

speed_av = 0 m/s / 2

speed_av = 0 m/s..

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