Question

v)The charge per unit area of a large flat sheet of charge is 3μC/m².Calculate the electric

field intensity at a point just near the surface of the sheet, measured from its midpoint

(ϵo=8.85×10-12 C²/Nm²).​

Answer 1

Given:

The charge per unit area of a large flat sheet of charge is 3μC/m².

To find:

Field intensity near the sheet ?

Calculation:

The general expression for field intensity due to charged sheet is :

$E = \dfrac{ \sigma}{2 \epsilon_{0}}$

$\implies E = \dfrac{3 \times {10}^{ - 6} }{2 \times 8.85 \times {10}^{ - 12} }$

$\implies E = \dfrac{3 \times {10}^{ - 6} }{17.7 \times {10}^{ - 12} }$

$\implies E = 0.169\times {10}^{ 6} \: N/C$

So, field intensity near the sheet is 0.169 × 10⁶ N/C.

Answer 2

Answer:

Given:

The charge per unit area of a large flat sheet of charge is 3μC/m².

To find:

Field intensity near the sheet ?

Calculation:

The general expression for field intensity due to charged sheet is :

E = \dfrac{ \sigma}{2 \epsilon_{0}}E=

2ϵ

0

σ

\implies E = \dfrac{3 \times {10}^{ - 6} }{2 \times 8.85 \times {10}^{ - 12} }⟹E=

2×8.85×10

−12

3×10

−6

\implies E = \dfrac{3 \times {10}^{ - 6} }{17.7 \times {10}^{ - 12} }⟹E=

17.7×10

−12

3×10

−6

\implies E = 0.169\times {10}^{ 6} \: N/C⟹E=0.169×10

6

N/C

So, field intensity near the sheet is 0.169 × 10⁶ N/C.