Question

v) the volume of a frustum of a cone is:
a) 1/31/(r12 +r22 + rir2)
b) 1/3 th (r13 + r23 + r1r2)
c) 1/3 th (r12 + r22 + rır2)
d) none of these​

Answer 1

Answer:

it will be none of these as the formula is

$1 \div 3\pi \times h((r1) ^{2} + (r2) ^{2} + r1r2)$

Answer 2

The volume of a frustrum of a cone is:

= 1/3πh ( r12+r22+(r1*r2) )

Hope my answer is correct...