Question

v. The zeroes of the quadratic polynomial 3x2 – 5x – 2 = 0 are: a)2,3 b)-2, 1/3 c)2, 1/3 d)-2,3​

Answer 1

Answer:

3x2 - 5x - 2 = 0

3x2 - 6x + x - 2 = 0

3x(x-2)+1(x-2) = 0

(3x+1) (x-2) = 0

x = -1/3 , 2.

Answer 2

Answer:

The zeroes of the given quadratic polynomial are

$\displaystyle{\boxed{\red{\sf\:x\:=\:2\:}}\sf\quad\:OR\:\quad\:\boxed{\red{\sf\:x\:=\:-\:\dfrac{1}{3}}}}$

Step-by-step-explanation:

The given quadratic equation is 3x² - 5x - 2 = 0.

We have to find the roots of the quadratic equation.

Now,

3x² - 5x - 2 = 0

⇒ 3x² - 6x + x - 2 = 0

⇒ 3x ( x - 2 ) + 1 ( x - 2 ) = 0

⇒ ( x - 2 ) ( 3x + 1 ) = 0

⇒ ( x - 2 ) = 0 , ( 3x + 1 ) = 0

⇒ x - 2 = 0 , 3x + 1 = 0

⇒ x = 2 , 3x = - 1

$\displaystyle{\therefore\:\underline{\boxed{\red{\sf\:x\:=\:2\:}}}\sf\quad\:OR\:\quad\:\underline{\boxed{\red{\sf\:x\:=\:-\:\dfrac{1}{3}}}}}$