Question

v)
Three resistors 10 ohm, 20 ohm and 30 ohm are
connected in series combination.
i] Find equivalent resistance of series
combination.
ii] When this series combination is
connected to 12V supply, by neglecting
the value of internal resistance, obtain
potential difference across each resistor.
[Ans: i) 60 ohm, ii) 2 V, 4 V, 6 V]​

Answer 1

Answer:

1. 10+20+30 = 60

2. 12/60×10=2

12/60×20=4

12/60*30=6

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Answer 2

10+20+30=60

V=ir

12=i60

I=12/60

1.v=12/60*10

V=2

2.v=12/60*20

V=4

3.v=12/60*30

V=6

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