Question

v=u +at
1. The speed of a body moving along a straight path changes 10m/s to 20m/s in 5 Find the acceleration of the body.​

Answer 1

Given: Velocity changes from 10 m/s, 20 m/s i.e Initial velocity (u= 10 m/s) Final velocity (v = 20 m/s) and time taken (t = 5s) .

Required to find :- Acceleration of the body .

ㅤㅤㅤ✇Explanation:-

ㅤㅤBy using first equation of motion

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \underline{ \dag \: \bf \red{v =u + at }}}$

Substituting the values,

$\: \: \: \: \: \: \: \: \: \: : \implies \: \sf \: 20 = 10 + a(5)$

$\: \: \: \: \: \: \: \: \: \: :\implies \: \sf \: 20 = 10 + 5a$

$\: \: \: \: \: \: \: \: \: \: :\implies \: \sf \: 20 - 10 = 5a$

$\: \: \: \: \: \: \: \: \: \: :\implies \: \sf \: 10 = 5a$

$\: \: \: \: \: \: \: \: \: \: :\implies \: \sf \: a = \cancel\dfrac {10}{5}$

$\: \: \: \: \: \: \: \: \: \: :\implies \: \sf \: a = 2 \: m/s {}^{2}$

Acceleration of the body is 2 m/sㅤ_________________________

Know more !

Equations of motion:-

$\large \: \: \: \dag \pink{ \sf \: v = u + at} \\ \dag \: \large\red{ \sf \: s = ut + \frac{1}{2}at {}^{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \dag \large\orange{ \sf \: v {}^{2} - u {}^{2} = 2as }$

where,

★ㅤv is the final velocity

★ㅤu is the initial velocity

★ㅤs is the distance covered

★ㅤa is the acceleration

★ㅤt is time taken