Question

(v=u+at).Can any one solve this equation with the help of velocity-time graph​

Answer 1

Equation of motion by graphical method.

1. Derivation of v=u +at. Initial velocity u at A =OA. ...
2. Derivation of S = ut +1/2 x at 2 The distance travelled by the body is given by area of the space between velocity time graph AB and time axis OC , which is equal to area of figure OABC. ...
3. Derivation of v2 = u2 + 2as.

Answer 2

$\huge\fbox\pink{A}\fbox\blue{n}\fbox\purple{S}\fbox\green{w}\fbox\red{E}\fbox\orange{r}$

${\blue{\tt{\underline{\underline{Deriving \ first \ equation \ of \ motion \ (v=u+at)}}}}}$

u ⇢velocity at time t1

v ⇢ velocity at time t2

If acceleration is represented as a , then , acceleration is defined as the rate of change of velocity.

${\tt}⇢a = \frac{v - u}{t2 \: - t1} \\ ⇢a = \frac{v - u}{t} \\☞ or \: v - u \: = at$

This is first equation of linear equations.

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Hope it's help ⚓⚓

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