Question

V=u+at check the dimensional correctness

Answer 1

Answer:

Explanation:

equation is v=u+at

dimensional formula of v=(M°LT^-1)

dimensional formula of u=(M°LT^-1)

dimensional formula of a=(M°LT^-2)

dimensional formula of t=(M°L°T)

LHS  is the dimensional formula of v=(M°LT^-1)

RHS=dimensional formula of u+dimensional formula of a×dimensional formula of t

=(M°LT^-1)+(M°LT^-2)×(M°L°T)

=(M°LT^-1)+(M°LT^-1)

=2(M°LT^-1)

2 is a dimensionless constant ,therefore LHS=RHS

Hence,the given relationship(equation)is dimensionally correct.

Answer 2

Given equation :- v = u + at

We know,

• dimensional formula of v = (M⁰LT⁻¹)

• dimensional formula of u = (M⁰LT⁻¹)

• dimensional formula of a = (M⁰LT⁻²)

• dimensional formula of t = (M⁰L⁰T)

__________________________

→ LHS  is the dimensional formula of v = (M⁰LT⁻¹)

→ RHS = dimensional formula of u + dimensional formula of a × dimensional formula of t

__________________________

= (M⁰LT⁻¹) + (M⁰LT⁻²) × (M⁰L⁰T)

= (M⁰LT⁻¹) + (M⁰LT⁻¹)

= 2(M⁰LT⁻¹)

2 is a dimensionless constant, so LHS = RHS

Hence,the given relationship(equation) is dimensionally correct.