Question

V = u + at
s = ut + 12 at2
2 as = v2 - u2

Derive them.....​

Answer 1

Answer:

Let initial velocity be u, final velocity be v, acceleration be a, time be t, distance or displacement be s.

As a= v-u/t

at=v-u

at+u=v

or v=u+at (1)

Also we know that

Average velocity= u+v/2

Also, distance covered= average velocity×time

s= u+v/2×t

Putting v=u+at in s=u+v/2×t, we get

s= u+(u+at) ×t

2

s= u+u+at ×t

2

s= 2ut+at²

2

s= 2ut + at²

2 2

s= ut+1/2at² (2)

Now from first equation of motion we get

v=u+at

v-u= t

a

t= v-u

a

Putting t's value in equation 2 we get

s=u(v-u/a)+1/2a(v-u/a)²

s= uv-u²/a+1/2a(v-u)²

a²

s= uv-u²/a+a(v-u)²

2a²

s= uv-u²/a+(v-u)²

2a

s= 2(uv-u²)+(v-u)²

2a

s= 2uv-2u²+v²+u²+2uv/2a

2as= -2u²+v²+u²

2as= v²-u² (3)

hope it helps u....

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