[v-u]x2 +[u-2v]x+v=0
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Answer:
ans = -3
Step-by-step explanation:
ans
given
v-u×2+u-2vx+v=0
v=?
u=?
x+x= 2x
v+v =2v
u+u=2u
given
2v+2x+2u+2-2+0+v
v= 3
x=2
u=2
therefore
3+2-2+2-2+0
= 5-2-2+0
= -3 ( cause 0 is not added. -+-=+ and -++= - ok )
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