v (x )=ax- bx^ 3 where a and b are constants .At which point on the x axis ,the field intensity becomes 0
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Answer: x = √(a/3b)
Explanation: E = - dV/dx
⇒ E = - d(ax- bx^3)/dx
⇒ E = - ( a - 3bx^2) = 3bx^2 - a
⇒ E = 0 = 3bx^2 - a
⇒ 3bx^2 = a
⇒ x^2 = a/2b
⇒ x = √(a/2b)
kaushikdey:
Thanks very much
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