(v) y = 5x4 + 6x3/2 + 9x
(vi) y = ax2 + bx + c
ds
Given s = 12 + 5t + 3, find
dt
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Given : y = 5x⁴ + 6x³/² + 9x , y = ax² + bx + c s = 12t² + 5t + 3,
To find : dy/dx & ds/dt
Solution:
d ( A + B + C) / dx = dA/dx + dB/dx + dC/dx
d ( xⁿ)/dx = nxⁿ⁻¹
y = 5x⁴ + 6x³/² + 9x
=> dy/dx = 5 * 4x³ + 6(3/2) x¹/² + 9
=> dy/dx = 20x³ + 9√x + 9
y = ax² + bx + c
dy/dx = 2ax + b
s = 12t² + 5t + 3,
=> ds/dt = 24t + 5
s = 12 + 5t + 3,
=> s = 5t + 15
=> ds/dt = 5
s = 12 + 5t + 3t²
=> ds/dt = 5 + 6t
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