Physics, asked by nivethaRajendran, 10 months ago

(v) y = 5x4 + 6x3/2 + 9x
(vi) y = ax2 + bx + c
ds
Given s = 12 + 5t + 3, find
dt​

Answers

Answered by amitnrw
4

Given :     y = 5x⁴  + 6x³/²  + 9x  ,   y = ax² + bx + c    s = 12t² + 5t + 3,

To find :  dy/dx    & ds/dt

Solution:

d ( A  +  B + C)  / dx  = dA/dx  + dB/dx  + dC/dx

d ( xⁿ)/dx = nxⁿ⁻¹

y = 5x⁴  + 6x³/²   + 9x

=> dy/dx  = 5 * 4x³   +  6(3/2) x¹/²   + 9

=> dy/dx  = 20x³   +  9√x   + 9

y = ax² + bx + c

dy/dx = 2ax  + b  

s = 12t² + 5t + 3,

=> ds/dt  = 24t  + 5

s = 12 + 5t + 3,

=> s  = 5t + 15

=>  ds/dt = 5

s = 12   + 5t + 3t²

=> ds/dt = 5 + 6t

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Answered by ujjwalchaubey2001
0

Answer:

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