Question

V1= [12/(12+10)]*15=90/11 V (works as a potential divider; V1 is voltage across 12 ohm resistor)...

V2=[40/(40+6)]*15=300/23 V (similar explanation as before)

I1 is V1/R so (90/11 V)/12 ohm = 15/22 A

I2 is V2/R so (300/23 V)/40 ohm = 15/46 A

power dissipated is I^2 * R

so power dissipated across 12 ohm resistor is (15/22 A)^2 * 12 ohm

power dissipated across 40 ohm resistor is (15/46 A)^2 * 40 ohm

(could u just calculate the last 2 urself...?:))

hope u understand

Answer 1

Answer:

hello dear friend stay safe and sound more cool

hello dear friend stay safe and sound more cool