V1=6i - 4j; +8k V2=ai+ 4j - 2k find a=?
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Explanation:
For what value of 'a' the vector 2i-3j+4k and ai+6j-8k are perpendicular to each other?
The two vectors, say A( 2i — 3j + 4k) and B(ai + 6j — 8k) are perpendicular, which means angle between them is 90°.
x = 90°
We know that
A.B = AB cos x
A.B = AB cos 90°
A.B = AB * 0
A.B= 0
(2i-3j+4k).(ai+6j-8k)= 0
On solving, we get 2a-18-32=0
a = 25
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