Question

v1*v2*2/v1+v2 derivation

Answer 1

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Answer 2

Answer:

Answer:

Lets take that the body is moving along a straight line , covers half of the distance with speed v₁ and the remaining half with speed v₂ .

The Average speed will be derived in the following way :-

From A to B

S = S / 2

v = v₁

t₁ = (S/2 ) / v₁

   = S / 2v₁

From B to C ,

S = S/2

v = v₂

t₂ = S / 2v₂                        [ as derived earlier ]

Average speed = total distance / total time

v = S / t₁ + t₂

v = S / ( S/2v₁ + S/2v₂ )

By taking S/2 as common ,

v = (S) / S/2( 1/v₁ + 1/v₁ )

S gets cancelled

v = 1 / (1/2)(1/v₁ + 1/v₂)

v = 1 / v₁ + v₂ / 2v₁v₂

v = 2v₁v₂ / v₁ + v₂                    

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