Question

V2, 8(x) = x + 2
11. Show that (p-1) is a factor of (p10-1) and also of (p11-1).​

Answer 1

Answer:

1) f(x) = p10 – 1

g(x)=p-1

g(0)=p=1

f(1) = 1 – 1 = 0

2) p(x) = p11 – 1

g(1) = 1 -1 = 0

hope it helps

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