v² - u = 2 as check whether it is dimensionally correct?
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v2 = u2 + 2as
, writing the dimensional formula for each of them
[LT-¹]²= [LT-¹]² + [LT-²] [L] [IL²T-²] = [L²T-²] + [L²T-²]
All the terms have the same dimensional formula & hence the Equation is dimensionally .
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