Question

v²-u²=2as
20² -(25/3)²=2×0.54×s​

Answer 1

Step-by-step explanation:

v= final velocity = [LT-¹]

u= initial velocity=[LT-¹]

a= acceleration =[LT-²]

s= distance= [L]

v²=u²+ 2as

=>v²-u²=2as

[LT-¹]²-[LT-¹]²=2[LT-²][L]

[L²T-²][L²T-²]=2[L²T-²]

2[L²T-²]=2[L²T-²]

Hence Proved

Answer 2

Answer:

The question is wrong write it properly