Question

v2 = u2 + 2as find its dimantaion
please give me answer​

Answer 1

Answer:

hhhbbngyuooojutte1tjjloihv

Answer 2

KNOW MORE

filledbookmark

USE APP

Sign in

Questions & Answers

CBSE

Physics

Grade 10

Units Of Measurement

Question

Answers

Related Questions

Check the accuracy of relation v2−u2=2as, where v and u are the final and initial velocities, a is the acceleration, and s is the distance.

Answer

VerifiedVerified

125.1k+ views

15.2k+ likes

Hint: In this question use the concept that the accuracy is dependent upon the dimension of the relation if the L.H.S and R.H.S dimension are equal then the accuracy of the given relation is right so use this concept to reach the solution of the question.

Complete Step-by-Step solution:

So the given relation is

v2−u2=2as

Here v = final velocity and the unit of velocity is m/s.

As we know that the dimension of meter is L and the dimension of second is T, so the dimension of final velocity is

v=[L][T]=[LT−1]

So the dimension of v2 is

v2=[LT−1]2=[L2T−2]

Now u = initial velocity whose unit is same as final velocity as both are velocities

So the velocity of u is

u=[L][T]=[LT−1]

So the dimension of u2 is

u2=[LT−1]2=[L2T−2]

Now take L.H.S of the given equation

⇒v2−u2

Now as we see that the dimension of v2 and u2 are same so the dimension of (v2−u2) is also same as dimension is independent of addition or subtraction

Therefore the dimension of (v2−u2) is [L2T−2]

So, L.H.S dimension = [L2T−2]

Now consider the R.H.S of the given equation

⇒2as

Here a = acceleration.

And the unit of acceleration is m/s2.

As we know that the dimension of meter is L and the dimension of second is T, so the dimension of final acceleration is

a=[L][T2]=[LT−2]

Now s = distance and distance is measured in meter or centimeter.

And the dimension of meter or centimeter is same = L

So the dimension of s = L

So the dimension of as = [LT−2][L]=[L2T−2]

Now as we know that the dimension is independent of scaling so the dimension of 2as is [L2T−2].

So R.H.S dimension = [L2T−2]

So as we see that the L.H.S dimension = R.H.S dimension = [L2T−2]

Hence the given relation is accurate.

So this is the required answer.

Note – That all physical quantities can be expressed in terms of seven fundamental base quantities such as mass, length, time , temperature, electric current, luminous intensity and amount of substance. These seven quantities are called seven dimensions of the physical world. We can use symbols instead of the names of the base quantities and they are represented in square brackets. M for mass, L for length, T for time, K for temperature, I for current, cd for luminous intensity and mol for the amount of substance. These will specify the nature of the unit and not its magnitude.