Question

v2-u2=2as graphically​

Answer 1

Answer:

s: area under velocity graph

Area of trapezium

1/2= (sum of all parallelogram)(h)

1/2 = (OA+CE)(AD)

1/2=(u+v)(t)

using 1st eqn that is v-u=at

v-u/a=t

s= 1/2 ( v+u/a)(v-u/a)

s= 1/2a (v2-u2)

2as = v2-u2

v2-u2= 2as

Answer 2

Hey mate here is your answer

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