Question

v2 = u2 + 2as what can you find with this ​

Answer 1

I can derive newton's third equation of motion from this

Answer 2

v=u+at -> t = v-u/a s = (v+u)t/2 so s = (v+u)*(v-u)/2a 2as = (v+u)(v-u) 2as = v2-u2 v2=u2+2as but i am having trouble understanding this way V2=(u+at)2 V2=(u+at)(u+at) V2=u2+a2t2+2uat - i cant understand how you get from this to; V2=u2+2a(ut+0.5at2) i know that s=u+u+at/2*t i.e s=u+v/2*t so with V2=u2+a2t2+2uat you have a*a t*t u+u+a+a+t+t you can remove 2a as V2=u2+2a(ut+0.5at2) this leaves a*a t*t u+u+t+t then remove u+u+a+t+t for s=u+u+at/2*t then i am left with a and t*t