Question

V2/V1 must me 5/10=.5 but in in hint value of log2 is given rather then log(.5), why? + solution ​

Answer 1

Answer:

You are so big....

Explanation:

Answer 2

Answer:

W=−2.303nRTlog10V2V1  

=−2.303×1040×2×300log10510

W=103.635cal

ΔU=0

∵q=ΔU−W

∴Q=−W=−103.635cal

Also when temperature is constant

P1V1=P2V2 or PV=constant

∴ΔH=ΔU+Δ(PV)=0+0=0

Explanation:

Mass of argon = 10 g

Temperature =  = 27 + 273 = 300 K

Initial volume = 10 L

Final volume = 5 L

Molar mass of argon = 40 g/mole

Value of R (in Cal/mole K) = 2 Cal/mole K

Formula used for Reversible isothermal system is,

For 'q'   :             ...........(1)

For ΔH  :   ΔH =            ...........(2)

First, we have to calculate the 'moles of argon'

Moles of argon =  =  = 0.25 moles

Now put all the given values in above formula (1), we get

= - 103.98045 Cal

And the value of ΔH is equal to zero. Because our system is in isothermal, this means system at constant temperature.

The formula of ΔH =  , and dT =0

Therefore, the value of  ΔH  become zero.

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