V3 x2 + 4x - 7V3 = 0
:: V3 x2 + |-3x – 713 = 0
:: x( ) - √3 ) = 0
(x - v3 ) ( ) = 0
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Answer:
In the figure given, seg DE ll side BC, if DE : BC = 3 : 5 then find A(ΔADE) : A(⟂ DBCE).In the figure given, seg DE ll side BC, if DE : BC = 3 : 5 then find A(ΔADE) : A(⟂ DBCE).In the figure given, seg DE ll side BC, if DE : BC = 3 : 5 then find A(ΔADE) : A(⟂ DBCE).In the figure given, seg DE ll side BC, if DE : BC = 3 : 5 then find A(ΔADE) : A(⟂ DBCE).In the figure given, seg DE ll side BC, if DE : BC = 3 : 5 then find A(ΔADE) : A(⟂ DBCE).In the figure given, seg DE ll side BC, if DE : BC = 3 : 5 then find A(ΔADE) : A(⟂ DBCE).In the figure given, seg DE ll side BC, if DE : BC = 3 : 5 then find A(ΔADE) : A(⟂ DBCE).In the figure given, seg DE ll side BC, if DE : BC = 3 : 5 then find A(ΔADE) : A(⟂ DBCE).In the figure given, seg DE ll side BC, if DE : BC = 3 : 5 then find A(ΔADE) : A(⟂ DBCE).In the figure given, seg DE ll side BC, if DE : BC = 3 : 5 then find A(ΔADE) : A(⟂ DBCE).