Question

vA=2v vD = 2v vE = -3v vG = 2v vH = 1v vAB = 10v Here, vAB indicates the voltage referenced from node b to node a. In other words, imagine vAB being identified in the diagram as having a "-" at node b and a "+" at node a. The other voltages are specified using the labeled references. Find vB and vAC

Answer 1

Answer:

vB=6v vAC=5v

Explanation:

it is given that vab=10 and considering the path of charges flowing through elements G, B and A for the applied voltage,

vab=10v=vG+vB+vA

10=2+vB+2

vB=6V

vAC is the voltage between nodes a and c, considering the path of charges flowing through elements A, D and H for the applied voltage

vAC=vA+vD+vH

vAC=2+2+1

vAC=5V

Note: there is another paths which can be chosen for vAC like through A,C,F and H. Then  vAC=vA+vC+vF+vH, you would have to find 2 unknown voltage so i easier earlier.