Question

विभाजित होता है, वह ज्ञात
Find the ratio in which the segment joining the points (1. - 3) and (4, 5) is
divided by x-axis ? Also find the coordinates of this point on x-axis.​

Answer 1

any point on the X axis is of the form (x,0)

let the ratio be k:1

Using section formula for Y coordinate

$0 = \frac{(1 \times - 3) + (5 \times k)}{k + 1} \\ 0 = - 3 + 5k \\ 3 = 5k \\ k = \frac{3}{5}$

since the ratio is k:1

therefore it can be written as

3/5:1

So the required ratio is

3:5

Now using section formula for X coordinate

$x = \frac{(1 \times 5) + (4 \times 3)}{5 + 3} \\ x = \frac{5 + 12}{8} \\ x = \frac{17}{8}$

here is your answer :)