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Given :
Two objects of masses 100g and 200g are moving along the same direction with velocities of 2m/s and 1m/s.
After collision first object moves at a velocity of 1.67 m/s.
To Find :
Velocity of second object after collision.
Solution :
❒ Since no net force acts on the system, linear momentum of whole system is conserved.
We know that momentum is measured as the product of mass and velocity.
It is a vector quantity having both magnitude as well as direction..
SI unit : N s
★ Initial momentum of system :
➛ m₁u₁ + m₂u₂
➛ (100)(2) + (200)(1)
➛ 200 + 200
➛ 400 N s
★ Final momentum of system :
➛ m₁v₁ + m₂v₂
➛ (100)(1.67) + 200v₂
➛ 167 + 200v₂
Initial momentum of system is equal to the final momentum of system.
➠ 400 = 167 + 200v₂
➠ 200v₂ = 400 - 167
➠ 200v₂ = 233
➠ v₂ = 233/200
➠ v₂ = 1.16 m/s