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Answer࿐
Given:
Perimeter of a rectangle = 260 cm.
Breadth of the rectangle = 60 cm.
To find:
The length of the rectangle.
The area of the rectangle.
Formulae used:
Perimeter of rectangle = 2(l+b) units
Area of rectangle = lb sq.units
Solution:
As per the given data, the known values are- the measure of perimeter and the measure of breadth. We're asked to find the length and area of the rectangle. How can we find its length? Simple! It's calculation can be carried out by substituting the given measures in the formula of perimeter of rectangle and solving for the unknown value, i.e, the measure of length.
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↪️Finding the length of the rectangle:
On substituting the measures-
⟼ Perimeter = 2(l + b)
⟼260=2(l+60)
⟼260=2l+120
⟼(260−120)=2l
⟼140=2l
⟼ 2140 =l
⟼ 70cm=Length
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↪️Finding the area of the rectangle:
Length = 70 cm
Breadth = 60 cm
On substituting measure
⟼ Area = lb sq.units
⟼Area=(70×60)
⟼ Area=4200cm 2
∴ Thelengthoftherectangleis 70 cm anditsareais4200 cm
2
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Some formulae for AREA:
Square = s² sq.units
Triangle = 1/2 (bh) sq.units
Trapezium = 1/2 h(a+b) sq.units
Parallelogram = bh sq.units
Rhombus = 1/2 d₁d₂ sq.units
Circle = πr² sq.units
Semi-circle = 1/2 πr² sq.units
Quadrant of circle = θ/360° πr² sq.units
Annulus = π(R² – r²)
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