Question

व्हाई डू यू थिंक ऑर्डिनरी मैन एंड वूमेन डेट 9 जनवरी की रिकॉर्ड ​

Answer 1

In the aforementioned polynomial, let a2 = x.

Now, the polynomial becomes,

x² + 4x + 5

Comparing with ax2 + bx + c,

Here, b2 – 4ac = 42 – 4(1)(5) = 16 – 20 = -4

So, D = b2 – 4ac < 0

As the discriminant (D) is negative, the given polynomial does not have real roots or zeroes.