Question

विज्ञान की उन्नति और मानव जीवन​

Answer 1

Answer:

विज्ञान वरदान के रूप में : विज्ञान ने मनुष्य को अनेक सुख प्रदान किये हैं। जीवन के प्रत्येक क्रियाकलाप में विज्ञान का योगदान रहा है। विज्ञान ने मनुष्य की कल्पनाओं को सच कर दिखाया है। विज्ञान ने भाप, अणुशक्ति को अपने वश में करके मनुष्य के जीवन में चार-चाँद लगा दिए हैं।

Answer 2

$\Large\bf\pink{Let,}Let,</p><p></p><p>ABCD is a rhombus.</p><p>\Large{\underline{\underline{\bf{\purple{DIAGRAM}}}}} </p><p>DIAGRAM</p><p> </p><p> </p><p> </p><p> </p><p></p><p>\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,0){\line(1,3){1.5}}\put(0,0){\line(1,0){5}}\put(5,0){\line(1,3){1.5}}\put(1.5,4.5){\line(1,0){5}}\qbezier(1.56,4.5)(1.56,4.5)(5,0)\qbezier(6.45,4.5)(6.45,4.5)(0,0)\put(-0.5,-0.5){\sf B}\put(1,4.8){\sf A}\put(5.2,-0.5){\sf C}\put(6.7,4.75){\sf D}\put(3,1.6){\sf O}\end{picture}</p><p></p><p>\begin{gathered}\longmapsto\:\:\bf{AC\:=\:BC}--(1)\:(given) \\ \end{gathered} </p><p>⟼AC=BC−−(1)(given)</p><p> </p><p> </p><p></p><p>\begin{gathered}\longmapsto\:\:\bf{BC\:=\:AB}--(2)\:(side) \\ \end{gathered} </p><p>⟼BC=AB−−(2)(side)</p><p> </p><p> </p><p></p><p>\bf\red{From\:equ^n\:(1)\:\&\:(2),}Fromequ </p><p>n</p><p> (1)&(2),</p><p></p><p>\begin{gathered}\longmapsto\:\:\bf{AC\:=\:BC\:=\:AB} \\ \end{gathered} </p><p>⟼AC=BC=AB</p><p> </p><p> </p><p></p><p>\begin{gathered}\therefore\:\:\bf{\triangle{ABC}\:is\: equilateral\: triangle}. \\ \end{gathered} </p><p>∴△ABCisequilateraltriangle.</p><p> </p><p> </p><p></p><p>\Large\bf\pink{So,}So,</p><p></p><p>\bf{\angle{ABC}\:=\:60°}∠ABC=60°</p><p>\bf{\angle{BCA}\:=\:60°}--(3)∠BCA=60°−−(3)</p><p>\bf{\angle{CAB}\:=\:60°}--(4)∠CAB=60°−−(4)</p><p>\Large\bf\red{Similarly,}Similarly,</p><p></p><p>\bf{In\:\triangle{ADC},\:}In△ADC,</p><p></p><p>\bf{AD\:=\:DC}\:(Side)AD=DC(Side)</p><p>\bf{AD\:=\:BC}AD=BC</p><p>\Large\bf\red{But,}But,</p><p></p><p>\bf{BC\:=\:AC}BC=AC</p><p>\begin{gathered}\longmapsto\:\:\bf{AD\:=\:AC} \\ \end{gathered} </p><p>⟼AD=AC</p><p> </p><p> </p><p></p><p>\begin{gathered}:\implies\:\:\bf{AD\:=\:DC\:=\:AC} \\ \end{gathered} </p><p>:⟹AD=DC=AC</p><p> </p><p> </p><p></p><p>\begin{gathered}\therefore\:\:\bf{\triangle{DAC}\:is\: equilateral\: triangle}. \\ \end{gathered} </p><p>∴△DACisequilateraltriangle.</p><p> </p><p> </p><p></p><p>\bf{\angle{CAD}\:=\:60°}--(5)∠CAD=60°−−(5)</p><p>\bf{\angle{ADC}\:=\:60°}∠ADC=60°</p><p>\bf{\angle{DCA}\:=\:60°}--(6)∠DCA=60°−−(6)</p><p>\bf\red{From\:equ^n\:(3)\:\&\:(6)\:we\:get}Fromequ </p><p>n</p><p> (3)&(6)weget</p><p></p><p>\begin{gathered}:\implies\:\:\bf{\angle{BCA}\:+\:\angle{DCA}\:=\:60°\:+\:60°\:=\:120°} \\ \end{gathered} </p><p>:⟹∠BCA+∠DCA=60°+60°=120°</p><p> </p><p> </p><p></p><p>\begin{gathered}\therefore\:\:\bf{\angle{C}\:=\:120°} \\ \end{gathered} </p><p>∴∠C=120°</p><p> </p><p> </p><p></p><p>\bf\red{From\:equ^n\:(4)\:\&\:(5),}Fromequ </p><p>n</p><p> (4)&(5),</p><p></p><p>\begin{gathered}:\implies\:\:\bf{\angle{CAB}\:+\:\angle{CAD}\:=\:60°\:+\:60°\:=\:120°} \\ \end{gathered} </p><p>:⟹∠CAB+∠CAD=60°+60°=120°</p><p> </p><p> </p><p></p><p>\begin{gathered}\therefore\:\:\bf{\angle{A}\:=\:120°} \\ \end{gathered} </p><p>∴∠A=120°</p><p> </p><p> </p><p></p><p>\Large\bf\purple{Hence,}Hence,</p><p></p><p>The four angles of the rhombus are 120° , 60° , 120° & 60°.</p><p></p><p></p><p>\begin{gathered}\Large\mathbb\pink{THANKS} \\ \end{gathered} </p><p></p><p> </p><p> </p><p></p><p>\begin{gathered}\Large\mathbb\green{HOPE\: IT'S\: HELPFUL} \\ \end{gathered} </p><p>HOPEIT </p><p>′</p><p> </p><p>$