Question

वेपर डेंसिटी ऑफ अमोनिया 8.5,85 ग्राम ऑफ NH3​

Answer 1

Answer:

Vapor density *2=molecular massHere, 8.5*2=molecular mass of NH3Molecular mass of NH3=17g/molNow, no. of moles=given mass/molecular massTherefore, no. of moles=85/17=5molesSince one mole of any gas is equal to 22.7 Litre at NTPTherefore, 5 moles of gas will cover a volume =5*22.7=113.5 Litre.