Question

विस्तार करा: $\bigg \lgroup 1-\frac{1}{a} \bigg \rgroup^3$

Answer 1

विस्तार सूत्र:

$( {x-y)}^{3} = {x}^{3} - {y}^{3} - 3 {x}^{2} y + 3x {y}^{2}$
विस्तार करा:$\bigg \lgroup 1-\frac{1}{a} \bigg \rgroup^3$

$x = 1\\ \\ y= \frac{1}{a}$
$\bigg( { 1 - \frac{1}{a} \bigg)}^{3} = {1}^{3} - \bigg({ \frac{1}{a} \bigg)}^{3} - 3 {(1)}^{2} \bigg( \frac{1}{a}\bigg) + 3(1) {\bigg( \frac{1}{a}\bigg) }^{2} \\ \\ = 1 - \frac{1}{ {a}^{3} } - \frac{3}{a} + \frac{3}{a^{2}}$
विस्तार:

$\bigg \lgroup 1-\frac{1}{a} \bigg \rgroup^3 =1 - \frac{1}{ {a}^{3} } - \frac{3}{a} + \frac{3}{a^{2}}$