Question

विस्तार करा: $\bigg \lgroup \frac{p}{3} + \frac{q}{4}\bigg \rgroup ^{2}$

Answer 1

प्रश्नः

विस्तार करा: ${(\frac{p}{3} + \frac{q}{4} )}^{2}$

उत्तरः

सुत्र: ${(a + b)}^{2} = {a}^{2} + {b}^{2} 2ab$

$= > {(\frac{p}{3} + \frac{q}{4} )}^{2} \\ \\ = > {( \frac{p}{3} )}^{2} + {( \frac{q}{4} )}^{2} + 2(\frac{p}{3})( \frac{q}{4} ) \\ \\ = > \frac{ {p}^{2} }{9} + \frac{ {q}^{2} }{16} + \frac{pq}{6}$