Question

वायु
कि
10. A car is travelling at a speed of 90 km/h.
Brakes are applied so as to produce a uniform
acceleration of - 0.5 m/s2. Find how far the car
will go before it is brought to rest?
(1 Point)
ढती
(a) 8100 m
ढ़ने
(b) 900m
ग एक
पर वा
(c) 625 m
(d) 620 m
sha​

Answer 1

Answer:

Solution :

⏭ Given:

✏ Initial speed of car = 90kmph

✏ Final speed of car = 0

✏ Acceleration produced in car = 0.5

⏭ To Find:

✏ Distance covered by the car before it is brought to rest.

⏭ Concept:

✏ This question is completely based on concept of stopping distance.

⏭ Formula derivation:

✏ As per second equation of kinematics

✏ Negative sign shows retardation.

⏭ Terms indication:

✏ S denotes distance covered by body

✏ u denotes initial velocity

✏ v denotes final velocity

✏ a denotes acceleration

⏭ Conversation:

✏ 90 kmph = 25 mps

⏭ Calculation:

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