व्यापारिक बट्टा क्या है?
Answers
Answer:
ok
✬ Length = 11 m ✬
✬ Width = 8 m ✬
Step-by-step explanation:
Given:
Perimeter of rectangle is 38 m.
Length is 5 m less than twice its width.
To Find:
Length of dimensions of rectangle.
Solution: Let the width of rectangle be x m. Therefore,
➙ Length = 5 less than two time of x.
➙ Length = (2x – 5) m
As we know that for rectangle
★ Perimeter = 2 × ( Length + Width ) ★
Perimeter is 38 m.
\implies{\rm }⟹ 38 = 2 ( 2x – 5 + x )
\implies{\rm }⟹ 38/2 = ( 2x – 5 + x )
\implies{\rm }⟹ 19 = 3x – 5
\implies{\rm }⟹ 19 + 5 = 3x
\implies{\rm }⟹ 24/3 = x
\implies{\rm }⟹ 8 = x
So measure of width of rectangle is 8 m and measure of length = 2(8) – 5 = 11 m.
✬ Length = 11 m ✬
✬ Width = 8 m ✬
Step-by-step explanation:
Given:
Perimeter of rectangle is 38 m.
Length is 5 m less than twice its width.
To Find:
Length of dimensions of rectangle.
Solution: Let the width of rectangle be x m. Therefore,
➙ Length = 5 less than two time of x.
➙ Length = (2x – 5) m
As we know that for rectangle
★ Perimeter = 2 × ( Length + Width ) ★
Perimeter is 38 m.
\implies{\rm }⟹ 38 = 2 ( 2x – 5 + x )
\implies{\rm }⟹ 38/2 = ( 2x – 5 + x )
\implies{\rm }⟹ 19 = 3x – 5
\implies{\rm }⟹ 19 + 5 = 3x
\implies{\rm }⟹ 24/3 = x
\implies{\rm }⟹ 8 = x
So measure of width of rectangle is 8 m and measure of length = 2(8) – 5 = 11 m.