Math, asked by ghfgk8555, 1 year ago

वह छोटी से छोटी संख्या ज्ञात कीजिए जिसे 2432 36 से भाग देने पर प्रत्येक दशा में 5 शेष बचे
Find out the smallest number which is divisible by 2432 36 leaving a remainder of 5 in each case.

Answers

Answered by IamIronMan0
0

Answer:

First find LCM of 2432 , 36 = 21888

So number will be = 21888 + 5 = 21893

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