Question

वह छोटी से छोटी संख्या ज्ञात कीजिए जिसमें 6,9,15,18 से भाग देने पर प्रत्येक दशा मे शेष 4 बचता है लेकिन 7 से भाग देने पर शेष 0 बचता है​

Answer 1

first you have fine LCM of 6 9 15 and 18 and then add 4 to, and also we have to multiply the L.C.M. by 7.

as LCM of 6 9 15 and 18 = 90.

show the number can be 94 but its not divisible by 7

let's find another no.

for this we have to to find some consecutive multiples of 90

• 90
• 180
• 270
• 360
• 450,.etc

in each in each of the above number we have to check it by adding 4 and by dividing 7 to the obtained result.

as 94 is not divisible by 7

184 is not divisible by 7

274 is not divisible by 7

but 364 is absolutely divisible by 7.

therefore 364 is that least number which when divided by 6 9 15 and 18 leaves remainder 4 and accurately divided by 7.

“364”