Question

वह सबसे छोटी संख्या ज्ञात करें जिससे 12 15 20 24 और 45 से भाग देने पर 8 शेष बचे7​

Answer 1

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Answer:

The required number is 345.

Step-by-step explanation:

Consider the provided information.

We need to find a smallest number that when added to 15 is exactly divisible by 28, 30, 36 and 45

First find the LCM of the numbers.

8 = 2×2×2

30 = 2×3×5

36 = 2×2×3×3

45 = 3×3×5

The LCM of the numbers are: 2×2×2×3×3×5 = 360

Now subtract 15 from 360.

360 - 15 = 345

Hence, The smallest number that when added to 15 is exactly divisible by 28, 30, 36 and 45 is 345.