vaibhav inherited Rs. 12000.00. He invested a part of it as 10% and the rest at 12%. His annual income from these investments is Rs 1280. How much he invested at rate of 12%?
Answer fully
and answer is rs.4000
Answers
Answered by
7
let part invested at 12% be x
hence part invested at 10% is 12000-x
therefore 12/100x+10/100(12000-x)=1280
=>0.12x+0.1(12000-x)=1280
=>0.12x+1200-0.1x=1280
=>0.02x=80
=>x=80/0.02
=>x=4000
hence part invested at 10% is 12000-x
therefore 12/100x+10/100(12000-x)=1280
=>0.12x+0.1(12000-x)=1280
=>0.12x+1200-0.1x=1280
=>0.02x=80
=>x=80/0.02
=>x=4000
Answered by
1
Answer:
Rs.4000
Step-by-step explanation:
Let the invested part at 12% be x
Hence the part invested at 10% is 12000-x
Therefore
12/100 x + 10/100 (12000-x) =1280
0.12x+0.1(12000-x)=1280
0.12x+1200-0.1x=1280
0.12x-0.1x=1280-1200
0.02x=80
x=80/0.02
x=8000/2
x=4000
Answer: Rs 4000
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