Question

वक्र y = x² - 4x -5 के बिंदु x = -2 पर स्पर्श रेखा का समीकरण ज्ञात कीजिए

Answer 1

Answer:

$\huge\underline{\underline{\mathfrak\red{hola mate}}}$

$\huge\boxed{\fcolorbox{red}{lime}{given}}$

putting value

x = -2

y = -2² - 4×(-2) - 5

= 4 + 8 - 13

= 12 - 13

= -1

$\huge\boxed{\fcolorbox{purple}{lime}{Thanks}}$

Step-by-step explanation:

Answer = 1

given ,

Answer 2

Answer:

$\huge\mathfrak\red{solution}$

putting value

x = -2

y = -2² - 4×(-2) - 5

= 4 + 8 - 13

= 12 - 13

= -1

$\huge\boxed{\fcolorbox{purple}{lime}{Thanks}} </p><p>$

Step-by-step explanation:

Answer = 1

given ,